Part 1
I. What is one reason that the bleeding would not stop? *Hint: Look at the case study title
The bleeding wouldn't stop because Leopold has hemophilia.
II. a.) What is a gene?
The basic unit of heredity which governs the expression of particular traits and can be passed to offspring.
b.) What is an allele?
A different form of the same gene occurring on homologous chromosomes.
c.) What is a sex-linked trait?
Trait that is controlled by genes on either the X or Y chromosome.
d.) Who is more likely to get hemophilia, males or females? Why?
Males are more likely to get the disease because they only need one copy of the recessive allele, while the females need two recessive copies of the allele.
II. Seeing as hemophilia is an x linked recessive disorder, consider the following:
a. What would be the genotype of a hemophiliac male?
X(h)Y
b. What would be the genotype of a hemophiliac female?
X(h)X(h)
IV. If a mother is a carrier for hemophilia and the father does not have hemophilia, could their daughter get hemophilia? Explain.
No the daughter could not get hemophilia because she would need two copies of the recessive allele. While she could get one copy from her mother, she would only get a dominant allele from her father, therefore she cannot have hemophilia.
V. If neither of Leopold's parents have hemophilia, but Leopold does, what must the genotypes of his parents be? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
I. What is one reason that the bleeding would not stop? *Hint: Look at the case study title
The bleeding wouldn't stop because Leopold has hemophilia.
II. a.) What is a gene?
The basic unit of heredity which governs the expression of particular traits and can be passed to offspring.
b.) What is an allele?
A different form of the same gene occurring on homologous chromosomes.
c.) What is a sex-linked trait?
Trait that is controlled by genes on either the X or Y chromosome.
d.) Who is more likely to get hemophilia, males or females? Why?
Males are more likely to get the disease because they only need one copy of the recessive allele, while the females need two recessive copies of the allele.
II. Seeing as hemophilia is an x linked recessive disorder, consider the following:
a. What would be the genotype of a hemophiliac male?
X(h)Y
b. What would be the genotype of a hemophiliac female?
X(h)X(h)
IV. If a mother is a carrier for hemophilia and the father does not have hemophilia, could their daughter get hemophilia? Explain.
No the daughter could not get hemophilia because she would need two copies of the recessive allele. While she could get one copy from her mother, she would only get a dominant allele from her father, therefore she cannot have hemophilia.
V. If neither of Leopold's parents have hemophilia, but Leopold does, what must the genotypes of his parents be? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
The genotype of the mother would have to be X(H)X(h) and the genotype of the father would have to be X(H)Y.
Part II
I. If a hemophiliac female were to have a son with a normal male, what would be the probability of the son having hemophilia? Use a punnett square to show your answer. X(h)X(h) x X(H)Y
I. If a hemophiliac female were to have a son with a normal male, what would be the probability of the son having hemophilia? Use a punnett square to show your answer. X(h)X(h) x X(H)Y
The probability of having a hemophiliac son would be 50%.
II. What would be the phenotype of a female who was not a hemophiliac and also not a carrier?
X(H)X(h)
III. What is the relation of hemophilia to the sex chromosomes?
A person will get hemophilia if they are homozygous recessive for hemophilia. These alleles are on the x chromosome which is a sex chromosome.
IV. Why weren’t Queen Victoria’s other children affected?
They were not affected because they did not receive the necessary recessive alleles to give them hemophilia.
Part III
I. Irene: X(H)X(h)
Henry: X(H)Y
II. a.) Hemophiliac Male: 25%
b.) Carrier Female: 25 %
c.) Unaffected offsprings: 50%
111. (See graph below)
I. Irene: X(H)X(h)
Henry: X(H)Y
II. a.) Hemophiliac Male: 25%
b.) Carrier Female: 25 %
c.) Unaffected offsprings: 50%
111. (See graph below)
Part 4
1. Seeing as Alice of Athlone was a carrier, could she have a hemophiliac son with a man who was not a hemophiliac? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
1. Seeing as Alice of Athlone was a carrier, could she have a hemophiliac son with a man who was not a hemophiliac? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
Yes it is possible for her to have a hemophiliac son if the father is not a hemophiliac.
11. If Rupert (hemophiliac) was to have a daughter with woman who was a carrier, what percentage of the females would have hemophilia? Use a punnett square to show your answer.
X(H)X(h) x X(h)Y
11. If Rupert (hemophiliac) was to have a daughter with woman who was a carrier, what percentage of the females would have hemophilia? Use a punnett square to show your answer.
X(H)X(h) x X(h)Y
50% of the females would have hemophilia.
III. In order for the Duke of Kent, who does not have hemophilia, to be the father of Queen Victoria, what must be the genotype of her mother if she did not have hemophilia? Explain.
Seeing as the genotype of the Duke of Kent would have to be X(H)Y and Queen Victoria's genotype is X(H)X(h), this means that she must have gotten the recessive allele from her mother. Seeing as her mother did not have hemophilia, this means that she must have been a carrier therefore her genotype would be X(H)X(h).
IV. Is it possible for Queen Victoria to have a hemophiliac daughter if the father is not a hemophiliac? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
Seeing as the genotype of the Duke of Kent would have to be X(H)Y and Queen Victoria's genotype is X(H)X(h), this means that she must have gotten the recessive allele from her mother. Seeing as her mother did not have hemophilia, this means that she must have been a carrier therefore her genotype would be X(H)X(h).
IV. Is it possible for Queen Victoria to have a hemophiliac daughter if the father is not a hemophiliac? Use a punnett square to show your answer.
X(H)X(h) x X(H)Y
No it is not possible. The daughter would need to get a recessive allele from both parents, but the father does not have a recessive allele to pass down to her.